Question

three cubes each of volume 216cm^3 are joined end to end. Find surface area of resulting cuboid

Answer 1

$<b>Heya mate. (^_-). Solution below.$✓✓
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♥ Volume of 1 cube = 216 cm³


But, volume of cube = a³(a = edge)

=> a³ = 216

=> a = ³√216

=> a = 6 cm



•°• Edge of one cube = 6 cm




♥ Now, three cubes are joined end to end.

Then, dimensions of resulting cuboid,

length = 6 + 6 + 6 = 18 cm

breadth = 6 cm

height = 6 cm



♥ Then, Total surface area of the cuboid,

= 2(lb + bh + hl)

= 2 [(18 × 6) + (6 × 6) + (6 × 18)]

= 2 [108 + 36 + 108]

= 2(252)

= 504 cm²


•°• T.S.A of the resulting cuboid = 504 cm².
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Thank you.. ^_^

Answer 2

Edge of cube=3✓27=3cm

Length of resulting cuboid,l=3+3+3=9cm.

Breath of resulting cuboid,b=6cm

Height of resulting cuboid=6cm.

T.S.A of cuboid=2(lb+bh+lh)

=2(9°6+6°6+9°6)

=2(54+36+54)

=2°147 =294cm square

Hope this helps ❤️❤️

Please mark as brainliest ❤️