Three cubes each of volume 64cm^3 are joined end to end to form a cuboid . Find the total surface area of the cuboid so formed
Answers
Answered by
17
Answer:
224 sq. cm.
Step-by-step explanation:
why
Volume of each cube = 64 cm3
Thus, side of each cube = 4 cm.
So, the dimensions of cuboid are 4 4 12.
Surface area of the cuboid = 2[4 4 + 4 12 + 12 4]
= 224 sq. cm.
Answered by
25
Answer:
224 cm2
Step-by-step explanation:
Let l be the side of the cube and L, B, H be the dimensions of the cuboid
Since l3 = 64 cm3 ∴ l = 4 cm
Total surface area of cuboid is 2[LB + BH + HL],
Where L = 12, B = 4 and H = 4 = 2 (12 × 4 + 4 × 4 + 4 × 12) cm2 = 224 cm2
Therfore, total surface area of cuboid is 224 cm2
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