Question

Three cubes each of volumes 216 cm^3 are joined end to end to form a cuboid. Find TSA?

Answer 1

hey mate refer the attachment for the answer

Answer 2

$\huge\underline\mathbb\blue{GIVEN:-}$

• Volume of cube = 216 cm³

$\huge\underline\mathbb\blue{TO\:FIND:-}$

Find the T.S.A. of the resulting Cuboid = ?

$\huge\underline\mathbb\blue{SOLUTION:-}$

We have given the volume of cube is 216 cm³. Then,

Edge of each cube =$\sqrt[3]{216}$

Edge of each cube = $\bf{6 cm}$

The dimensions of the cuboid so formed are:

Length of resulting cuboid(l) = ( 6 + 6 + 6) cm

$\red\implies$$\rm\red{l = 18\: cm}$

Breadth of resulting cuboid,(b)

$\red\implies$$\rm\red{b = 6 cm}$

Height of resulting cuboid(h),

$\implies$$\rm\red{h = 6 cm}$

We know that the formula to find the Total Surface area of cuboid is :- $\rm{2(lb + bh + hl)}$

Now, putting the values in the formula

$\small{\implies{\sf}}$$\rm{ 2(18\times6 + 6 \times6 + 18\times 6){cm}^{2}}$

$\small{\implies{\sf}}$ $\rm{2(108 + 36 + 108) {cm}^{2}}$

$\small{\implies{\sf}}$ $\rm{2(252) {cm}^{2}}$

$\large{\boxed{\bf{\red{ T.S.A. = 504\: {cm}^{2}}}}}$