Three cubes each side 5 cm are joined end to end.Find the surface area of resulting cuboid.
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Length of each side of the cube = 5 cm
Now, 3 cubes are joined end-to-end.
∴length of cuboid, l = (5 + 5 + 5) cm = 15 cm
breadth of cuboid, b = 5 cm
height of cuboid, h = 5 cm
∴Surface area of the cuboid = 2(lb + bh + hl)
= 2( 15 × 5 + 5 × 5 + 5 × 15 ) cm2
=350cm2
Now, 3 cubes are joined end-to-end.
∴length of cuboid, l = (5 + 5 + 5) cm = 15 cm
breadth of cuboid, b = 5 cm
height of cuboid, h = 5 cm
∴Surface area of the cuboid = 2(lb + bh + hl)
= 2( 15 × 5 + 5 × 5 + 5 × 15 ) cm2
=350cm2
Answered by
10
☺☺ HERE IS YOUR ANSWER ☺☺
___________________________________________________________________
Three cube of side 5cm joined and form cuboid.
length of cuboid = 15cm
height of cuboid = 5cm
breadth of cuboid = 5cm
T.S.A of cuboid = 2(lb+bh+jl)
=2(15×5 + 5×5 + 5×15)
=2(75 + 25 + 75)
=2(175)
=350cm^2
_________________________________________________________________
☺ HOPE IT HELPS YOU ☺
THANKS...
___________________________________________________________________
Three cube of side 5cm joined and form cuboid.
length of cuboid = 15cm
height of cuboid = 5cm
breadth of cuboid = 5cm
T.S.A of cuboid = 2(lb+bh+jl)
=2(15×5 + 5×5 + 5×15)
=2(75 + 25 + 75)
=2(175)
=350cm^2
_________________________________________________________________
☺ HOPE IT HELPS YOU ☺
THANKS...
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