Math, asked by Winkingblack, 11 months ago

Three cubes of a metal whose edges are in the ratio 3:4:5 are melted and converted into a
single cube whose diagonal is 12v3 cm. Find the edges of the three cubes.​

Answers

Answered by parthiv2002
8

diagonal =

  \sqrt{} ({(\sqrt{2} a) }^{2}  + {a}^{2} ) = 12 \sqrt{3}

squaring \: both \: sides  \\    { (\sqrt{2})a }^{2}  +  {a}^{2}  = 144 \times 3 \\(  \sqrt{2}  + 1) {a}^{2}  = 144 \times 3 \\  {a }^{2}  = 144 \times 3 \div (  \sqrt{2}  + 1) \\ a = 13 \\ using \: a \: find \: edges \: of \: cubes \: using \\  \: following \: formula

27x^3+64x^3+125x^3=13×13×13

edges are

3x,4x,and 5x

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