Question

three cubes of iron whose are 6cm,8cm ,10cm are melted to form a single cube.

Answer 1

Hi Friend ✋✋✋

Plz mention the Quest properly....

Volume of three small cubes = Volume of large cube formed by melting 3cubes.

A = side of large cube..

6³ + 8³ + 10³ = A³

216 + 512 + 1000 = A³

A³ = 1728 cm³ ( volume )

A = 12 cm

Hope it is enough....

Answer 2

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Volume of the newly formed cube = Volume of the other three cubes which are                                                                  melted 
The edge of the newly formed cube (a) = x

The edge of first cube (a1) = 6 cm

The edge of second cube (a2) = 8 cm

The edge of third cube (a3) = 10cm 

             volume of newly formed cube = 6^3 + 8^3 + 10^3 
             volume of newly formed cube = 216 + 512 + 1000
              volume of newly formed cube = 1728

The volume of newly formed cube = 1728
                                                    x^3 = 1728
                                                        x = cube root of 1728
                                                        x = 12

Therefore the edge of the newly formed cube is 12 cms.

Hope it helped......