Three cubes of iron whose edges are 6 c.m., 8 c.m., 10 c.m. respectively are melted and
formed into a single cube. The edge of the new cube is
Answers
Answer:
Edge of new cube = 12 cm
Step-by-step explanation:
Given---> Edges of three cubes are 6cm, 8cm, 10cm repectively .
To find ---> Edge of new cube formed by melting three old cubes .
Solution --->
ATQ,
Edge of first cube = 6cm
Edge of second cube = 8cm
Edge of third cube = 10cm
We know that ,volume of cube = edge³
Volume of first cube = ( 6 )³
= 216 cm³
Volume of second cube = ( 8 )³
= 512 cm³
Volume of third cube = ( 10 )³
= 1000 cm³
Let edge of new cube formed by melting of old cubes be a .
Volume of new cube = a³
New cube is formed by melting three old cubes so volume of new cube is equal to sum of three old cubes. So
Volume of new cube = Sum of three old cubes
=> a³ = 216 + 512 + 1000
=> a³ = 1728
=> a³ = (12)³
=> a = 12 cm
So edge of new cube = 12 cm
edge of new cube 12cm
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