Three cubes of iron whose edges are 6cm 8cm and 10cm respectively are meltedoing and formed into a single cube find the edge of a new cube so formed
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hey
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volume of cube = (a)^3
volume of 3 cubes = volume of new cube formed by recasting
(6)^3+(8)^3+(10)^3=(a)^3
216+512+1000=(a)^3
1728=(a)^3
√12×12×12=a
a= 12 cm
hence edge of new cube formed is 12 cm
hope helped
______________
______________
volume of cube = (a)^3
volume of 3 cubes = volume of new cube formed by recasting
(6)^3+(8)^3+(10)^3=(a)^3
216+512+1000=(a)^3
1728=(a)^3
√12×12×12=a
a= 12 cm
hence edge of new cube formed is 12 cm
hope helped
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