Three cubes of iron with sides 3cm,4cm and 5cm are melted to form a new cube.What is the side of the new cube
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Given
We melt 3 cubes of side 3cm, 4cm, 5cm
Volume of cube =a³
After melt the cube the total volume we
=3³+4³+5³=27+64+125=216cm³
The sum of volume of all three cubes = volume of new cube
Sum of volume 216cm³
So volume of new cube =216cm³
Side =A
A³=216cm³
![a = \sqrt[3]{216} a = \sqrt[3]{216}](https://tex.z-dn.net/?f=+a+++%3D+++%5Csqrt%5B3%5D%7B216%7D+)
A=6cm
This is ur ans hope it will help you in case of any doubt comment below
We melt 3 cubes of side 3cm, 4cm, 5cm
Volume of cube =a³
After melt the cube the total volume we
=3³+4³+5³=27+64+125=216cm³
The sum of volume of all three cubes = volume of new cube
Sum of volume 216cm³
So volume of new cube =216cm³
Side =A
A³=216cm³
A=6cm
This is ur ans hope it will help you in case of any doubt comment below
tnwramit1:
tnx for brainliest
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