Three cubes of metal whose edges are 6 cm, 8 cm and 10 cm respectively are melted to form a single cube. Find The edge of the new cube.
Answers
Answered by
8
hey dude ur answer is here.............--
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volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cube root of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm.
thanks......!
____________________________________
volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cube root of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm.
thanks......!
Answered by
6
Answer:
Step-by-step explanation:
Given cubes of side lengths 6 cm, 8 cm, 10 cm.
Volume remains same so volume of new cube = sum of volumes of three cubes= v1+v2+v3
=6 cube +8 cube
+10 cube
=216+512+1000
=1728
Now volume of new cube =a cube
=1728=(12) cube
Edge of new cube =a=12.
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