Question

three cubes of metal whose edges are 6cm 8cm and 10cm are melted and one new cube is formed. find the total surface area of the new cube

Answer 1

${a}^{3} + {a}^{3} + {a}^{3} = {a}^{3}$
${6}^{3} + {8}^{3} + {10}^{3} = {a}^{3}$
$216 + 512 + 1000 = {a}^{3}$
${a}^{3} = 1728$
a = 12
$TSA \: = \: 6 {a}^{2} \\ TSA = 6 \times 12 \times 12$

TSA = 864

Answer 2

Answer:

864cm2

Step-by-step explanation:

a3+a3+a3= new volume

$6^{3} + 8^{3} +10^{3}$=new volume

216+512+1000=1728

a3=1728

a=12

T.S.A=6a2

        =6*12*12=864cm2