three cubes of metal with address 5 cm 4 cm and 3 cm respectively are melted to form a single cube find the lateral surface of the new cube formed
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volume of cube with side of 5 cm = 125 cm^3
volume of cube with side of 4 cm = 64 cm ^3
volume of cube with side of 3 cm = 27 cm^3
volume of new cube = volume of cube 1 + volume of cube 2 + volume of cube 3
= 125+64+27
= 216 cm^3
As volume of cube = a^3
so cube root of 216 = 6 cm = to side of new cube
so, LSA of new cube = 4a^2
= 4×36
= 144 cm^2
volume of cube with side of 4 cm = 64 cm ^3
volume of cube with side of 3 cm = 27 cm^3
volume of new cube = volume of cube 1 + volume of cube 2 + volume of cube 3
= 125+64+27
= 216 cm^3
As volume of cube = a^3
so cube root of 216 = 6 cm = to side of new cube
so, LSA of new cube = 4a^2
= 4×36
= 144 cm^2
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