three cubes of metal with edges 5 cm 4 cm and 3 cm respectively are melted to form a single cube find the lateral surface area of the new cube formed
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let the side of the new cube formed be Xcm.
then,volume of cube1+volume of cube2+volume of cube 3=volume of the new cube
that is 5^3+4^3+3^3=X^3
that is 125+64+27=X^3
that is 216=X^3
that is X=6cm
then lateral surface area=4×edge^2
that is 4×6×6=144cm^2
then,volume of cube1+volume of cube2+volume of cube 3=volume of the new cube
that is 5^3+4^3+3^3=X^3
that is 125+64+27=X^3
that is 216=X^3
that is X=6cm
then lateral surface area=4×edge^2
that is 4×6×6=144cm^2
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