three cubes of metal with edges 5cm ,4cm and 3cm tepectively are melted to form a single cube. find the lateral surface area of the new cube
Answers
Answered by
1
Answer:
144
Step-by-step explanation:
let l be the side of a cube.
volume of lager cube formed = sum of vol of all cubes melted.
l^3 =5^3+4^3+3^3
l^3 =216
l=6
hence, lateral surface area of new cube is 4×l^2=4×36=144
Answered by
0
Answer:
Step-by-step explanation:
Volume of new cube=vol1+vol2+vol3
L^3=5^3+4^3+3^3
=125+64+27
=216
L=6
Hence L. S. A=4*L^2
=4*6*6
=24*6=144=ANSWER
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