Question

three cubes of side 'n' is placed one over another then the total surface area of the resultant solid is ?

Answer 1

Step-by-step explanation:

lenght will be n

breadth will be n

height will become 3n

then you can apply formula

Answer 2

The surface area of resultant solid is

$\bold{14n^2}$.

Step-by-step explanation:

We are given the following in the question:

Side of cube = n

Resultant solid:

The resultant solid is a cuboid with length 3n, breadth n and height n.

Total surface area of cuboid =

$S = 2(lb + bh + hl)$

where l is the length of cuboid, b is the breadth of the cuboid and h is the height of cuboid.

Putting the values, we have,

$S = 2\big((3n)(n) + (n)(n) + (n)(3n)\big)\\= 2(3n^2 + n^2 + 3n^2)\\S = 2(7n^2)\\S = 14n^2$

The surface area of resultant solid is $\bold{14n^2}$.

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