Question

Three cubes of sides 3cm, 4cm and 5cm are melted and a new cube is formed. Find the edge of the new cube. Give explaination how you did so.

Answer 1

$Edge \: of \: new \: cube = \sqrt[3]{ {3}^{3} + {4}^{3} + {5}^{3} } \\ \sqrt[3]{27 + 64 + 125} \\ \sqrt[3]{216} = 6$









MARK BRAINLIEST

Answer 2

Given,

Volume of 1st cube = 3cm

Volume of 2nd cube = 4cm

Volume of 3rd cube = 5cm

Let the volume of the new cube be l


A/Q

Volume of 1st cube + volume of 2nd cube + volume of 3rd cube = volume of new cube


$= > {3}^{3} + {4}^{3} + {5}^{3} = {l}^{3} \\ \\ = > 27 + 64 + 125 = {l}^{3} \\ \\ = > 216 = {l}^{3} \\ \\ = > l \: = 6$


side of the new cube = 6 cm