Question

Three cubes of silver with edges 3 cm ,4 cm, 5 cm are melted

Answer 1

Volume of the 1st cube is 3³ which is 9cm³
Volume of the 2nd cube is 4³ which is 64cm³
Volume of the 3rd cube is 5³ which is 125cm³

So volume of the new cube is 9+64+125=198cm³

Let side be a,
a³=198
a=5.82cm

TSA=203.2344cm²
Thus, cost for that area is 203. 234x3. 5
Which is 711. 319₹




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Answer 2

First emwe have to find volume of all three cube to know volume of big cube.

Volume of first cube = a^3
= 3^3 = 27
Volume of second cube = 4^3
= 64
Volume of third cube = 5^3
= 125

Volume of big single cube = 27+64+125
= 216

Volume of big cube = 216
a^3 = 6^3
a ( side of big cube) = 6

Total surface area of big cube = 6a^2
= 6(6×6)
= 6(36)
= 216

Cost of coating gold at Rs 3.50 = 216×3.50
= Rs 756

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