Three cubes of silver with edges 3 cm, 4 cm and 5 cm are melted and recast into a
single cube. Find the cost of coating the surface of the new cube with gold at the rate
of 3.50 per square centimetre.
[Hint. If a cm is the edge of a new cube, then a3 = 33 + 43 + 50
93 = 216 = (6)3 => a = 6.]
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Explanation:
Volume of first cube= 3×3×3
=27
Volume of 2nd cube=4×4×4
=64
Volume of 3rd cube=5×5×5
=125
Sum= 27+64+125
=216
cube root of 216 = 6
Total cost = 6×3.50
=21.
Therefore, 21Rs.
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