Question

Three cubes of silver with edges 3 cm, 4 cm and 5 cm are melted and recast into a single cube. Find the cost of coating the surface of the new cube with gold at the rate of Rs 3.50 per square meter.

Answer 1

$\huge\underline\mathfrak\blue{Answer}$

S1 = 3 cm

S2 = 4 cm

S3 = 5 cm

v of cube = s³

V1 = 3³ = 27 cm³

V2 = 4³ = 64 cm³

V3 = 5³ = 125 cm³

total volume = 27+64+125 = 216 cm³

V4 = 216 cm³

S4³ = 216

S4 = ³√216 = 6 cm

TSA of cube = 6s²

TSA = 6 × 6²

= 6 × 36 = 216 cm²

cost of gold plating = 216 × 3.5 = ₹756

therefore the cost of covering the new cube with gold will be ₹756

hope it helps :))

Answer 2

Answer:

The cost of coating the surface with gold is Rs 756.

Step-by-step explanation:

Referred to the attachments.