Three cubes of silver with edges 3cm,4cm and 5cm are melted and recarted into single cube find the cost of coating the surface of new cube with gold at rate 2.7 per square cm
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S1 = 3 cm
S2 = 4 cm
S3 = 5 cm
v of cube = s³
V1 = 3³ = 27 cm³
V2 = 4³ = 64 cm³
V3 = 5³ = 125 cm³
total volume = 27+64+125 = 216 cm³
V4 = 216 cm³
S4³ = 216
S4 = ³√216 = 6 cm
TSA of cube = 6s²
TSA = 6 × 6²
= 6 × 36 = 216 cm²
cost of gold plating = 216 × 2.7 = ₹583.2
therefore the cost of covering the new cube with gold will be ₹583.2
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