Physics, asked by nikithreddy34, 5 hours ago

Three cubes of volume v, V/4, and V/8 respectively are immersed in the same liquid. If the buoyant force exerted on the 3rd cube is 40 units, then 1) Buoyant force on 1st cube is 80 units. 2) Buoyant force on 1st cube is 320 units 3) Buoyant force on 2nd cube is 80 units 4) Buoyant force on 2nd cube is 320 units​

Answers

Answered by rp9861774
0

Answer:

1, 3 are correct

Explanation:

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