Three cubes of volumes, 1 cm3, 216 cm3 and 512 cm3 are melted to form a new cube.
What is the diagonal of the new cube? (approximately)?
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volume of melted cubes = volume of new cube formed
1+216+512=V(Let the vol of new cube be V)
729=V
V=729 cm3
In cubes,all the dimensions are equal
so length=breadth=height=A(let)
A*A*A=729cm3
A=9 Cm
length=breadth=9 cm
diagonal=(162)^1/2(on calculation)
1+216+512=V(Let the vol of new cube be V)
729=V
V=729 cm3
In cubes,all the dimensions are equal
so length=breadth=height=A(let)
A*A*A=729cm3
A=9 Cm
length=breadth=9 cm
diagonal=(162)^1/2(on calculation)
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