Physics, asked by ashvi00113, 1 month ago

Three cubic boxes of dimensions (2×2×2) cm3 , (3×3×3) cm3 , (4×4×4) cm3 of masses 15kg, 28 kg and 32 kg. Arrange these three boxes on a surface such a way the pressure exerted by their combinations is 1.5 times of the pressure exerted by the third box. ( g = 10 ms-2 , W = mg)​

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Answered by krazenvonsmith
0

Three cubic boxes of dimensions (8)

m300 (27) m300 (64) m300 of masses, 1500g, 2800g, and 32000g. m300 + 8 ÷ 15kg, the same with the 2 others.

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