Three cylinders each of height 16 cm and
radius of base 4 cm are placed on a plane
so that each cylinder touches the other
two. What is the volume of the region
enclosed between the three cylinders?
don't give me thereoitical answers please
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the required area = area of a ∆ABC -3 ×Area of 60° sectors
=( √3/4×8^2) - (3 × 60/360 × π 4^2)
= 16√3-8π
= 8(2√3-π)cm^2
Required volume = area of region × height
= 16 × 8(2√3-π)
=128 (2√3-π)cm3
hoep this will help you good luck
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