Question

Three cylinders each of height 16 cm and
radius of base 4 cm are placed on a plane
so that each cylinder touches the other
two. What is the volume of the region
enclosed between the three cylinders?

don't give me thereoitical answers please​

Answer 1

the required area = area of a ∆ABC -3 ×Area of 60° sectors

=( √3/4×8^2) - (3 × 60/360 × π 4^2)

= 16√3-8π

= 8(2√3-π)cm^2

Required volume = area of region × height

= 16 × 8(2√3-π)

=128 (2√3-π)cm3

hoep this will help you good luck