Three dice are rolled. Find the probability of getting a sum 5
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Total number of events n ( S ) = 6 3 = 216
And the sum of numbers as 5 in three throws. As :
{ 1 , 1 , 3 } , { 1 , 3 , 1 } , { 3 , 1 , 1 }, { 1 , 2 , 2 } , { 2 , 1 , 2 } , { 2 , 2 , 1 }
So,
Total number of desired events = n ( E ) = 6
Therefore,
Probability of getting the sum of numbers as 5 in three throws = 6/216
=1/36
And the sum of numbers as 5 in three throws. As :
{ 1 , 1 , 3 } , { 1 , 3 , 1 } , { 3 , 1 , 1 }, { 1 , 2 , 2 } , { 2 , 1 , 2 } , { 2 , 2 , 1 }
So,
Total number of desired events = n ( E ) = 6
Therefore,
Probability of getting the sum of numbers as 5 in three throws = 6/216
=1/36
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