Three dice are rolled simultaneously. What is the probability that exactly two of the dice will come up as the same number?
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In each case the different number may show on any of the three dice, so there is a total of six ways to make the throw. The total number of ways the dice can fall is 6x6x6, so the probability of making the throw is6/216, or 1 in 36. First, the statement that two of the dice must be the same is totally irrelevant.
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Answer:
90/216 ways =5/12
Step-by-step explanation:
1-p(different no.s)-p(same numbers)
1-(5/9)-(1/36)
1-21/36
5/12
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