Three dice are thrown. Given that they ha
sum of 8, the probability that one of them
a four is
Answers
Answer:
The total number of ways to roll an 8 with 3 dice is therefore 21, and the probability of rolling an 8 is 21/216, which is less than 5/36. heads out of 20 is (20 10 ) /220 ≈ 17.6
Answer:
The probability is 1/24.
Given:
Three dice are thrown. Given that they sum of 8,
To Find:
Find the probability that one of them a four is
Step-by-step explanation:
Probability:
The probability that an event will happen is called probability or probability. It is used extensively in the fields of statistics, mathematics, science, philosophy etc.
Probability = favorable events / total events
Total events = 6 x 6 x 6 = 216
Favorable events = number of events in which the sum is 8 and one of the dice is having count 4.
let first dice is having 4 , so other two should have sum 4, so combination for other two can be (1,3) (2,2) (3,1) = 3 events
so for other two dice when they have 4 , number of events when the other two would have sum 4 will also be 3 - 3 events
So total favorable events are 9
(4,1,3) (4,2,2) (4,3,1)
(1,4,3) (2,4,2) (3,4,1)
(1,3,4) (2,2,4) (3,1,4)
So probability = 9 /216
=1/24
Hence the probability is 1/24.