Question

Three dice are thrown simultaneously the probability of getting a sum of 15 is

Answer 1

the possible outcomes are 7 and three dices are thrown...simulataneously
p=7/3

Answer 2

Answer:

$\frac{5}{108}$

Step-by-step explanation:

$\implies \: sample \: space = {6}^{3} = 216 \\ \\ \implies \: no. \: of \: possible \: outcomes = 10 \\ \\ (555)(663)(636)(366)(456)(465)(564)(546)(654)(645) \\ \\ probability = \frac{possible \: outcomes}{sample \: space} \\ \\ \implies \: probability \: = \frac{10}{216} = \frac{5}{108}$

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i am very much sure this is correct answer