Question

Three dice are thrown simultaneously. What is the probability of getting three numbers whose product is odd

Answer 1

Answer:

probability should be1/18

Answer 2

P(E) = $\dfrac{1}{2}$

Step-by-step explanation:

When three dice are thrown simultaneously

Total number of possible outcomes = $6^3$

= 6 × 6 × 6 = 216

To find, the probability of getting three numbers whose product is odd = ?

Let E be the event of getting three numbers whose product is odd.

The total number whose product is odd = 108 and

The total number whose product is even = 108

Number of favourable outcomes = 108

∴ P(E) = $\dfrac{Number of favourable outcomes}{Number of favourable outcomes}$

= $\dfrac{108}{216}$

= $\dfrac{1}{2}$

Thus, P(E) = $\dfrac{1}{2}$