Math, asked by muhamadaon31, 4 months ago

three dice were thrown, the outcomes noted and added (The results can be 3, 4, 5, 6.......18).
four players played the game 10 times each. Their scores were
168 16, 18, 14, 6, 18, 9, 10, 15, 14, 3, 7, 9, 17, 11, 4, 12, 16
divide this data into class intervals of size 3 and draw a bar graph.

Answers

Answered by rkcomp31
1

Answer:

Step-by-step explanation:

1) MAXIMUM POSSIBLE CHANCES

6*6*6=216

POSSIBILITIES OF SUM= 3

1,,1,1 (1)

SO p=1/216

Possibility of 4

121,112,211, (3)

P=3/216=1/72

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5:

Possibility

113,122,131

212,221

311, (7)

P=7/216

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6,

114, 123,132,141

213,222,231

312,321

411

Total:10

P=10/216=5/108

Similarly you try fro 7 to 18

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