Question

Three dices are rolled.find the number of possible outcomes in which at least one dice show6

Answer 1

all three dice show a number other than '6', 5 * 5 *5 = 125 cases.  Total possible outcomes when three dice are thrown = 216. The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'. = 216 - 125 = 91. The required probability = 91/ 216