three different coins are tossed simultaneously find the probability of getting exactly one head
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3
Answer:1/3
Step-by-step explanation:
p(e)=no.ofpossible trails/total no. of trails
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6
sample space of three coins
S = {HHH , HHT , HTH, THH, TTT, TTH , THT, HTT }
n (S) = 6
let the event A be the that getting exactly one head .....
A = { TTH , THT , HTT }
n (A) = 3
p(A) = n(A) / n(S)
= 3 / 6
2
probability = 2
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