three different coins are tossed simultanepusly find the probabaility of getting exactly one head
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Total number of trials = 250.
Number of times three heads appeared = 70.
Number of times two heads appeared = 55.
Number of times one head appeared = 75.
Number of times no head appeared = 50.
In a random toss of 3 coins, let E1, E2, E3 and E4 be the events of getting three heads, two heads, one head and 0 head respectively. Then,
getting one head
P(getting one head) = P(E3)
Number of times one head appeared
= Total number of trials
= 75/250
= 0.30
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