Question

Three different container contains 403l, 424l and 465l of milk respectively. Find the capacity of a container wich can measure the milk of all the container in an exact number of times​

Answer 1

Correct Question :

Three different container contains 403l, 434l and 465l of milk respectively. Find the capacity of a container wich can measure the milk of all the container in an exact number of times.

Solution :

Given :

• Three different container contains 403l, 434l and 465l of milk respectively.

To find :

• The capacity of a container wich can measure the milk of all the container in an exact number of times =?

Step-by-step explanation :

Three different container contains 403l, 434l and 465l of milk respectively. [Given]

We have to find the capacity of a container wich can measure the milk of all the container in an exact number of times. So, the HCF (Highest Common Factor) of the given containers capacity.

HCF of 403, 434 and 465 :-

403 = 13 × 31

434 = 2 × 7 × 31

465 = 3 × 5 × 15 × 31

•°• HCF = 31.

Therefore, the capacity of a container wich can measure the milk of all the container in an exact number of times = 31 litres

Answer 2

$\bf\large{\underline{Question:-}}$

Three different container contains 403l, 424l and 465l of milk respectively. Find the capacity of a container wich can measure the milk of all the container in an exact number of times.

$\bf\large{\underline{Given:-}}$

• Different container contain 403 , 424 and 465 litre milk.

$\bf\large{\underline{To find:-}}$

• Find the capacity of a container which can measure the milk of all the container in an exact number of times=?

$\bf\large{\underline{Solution:-}}$

→ on factorization of 403,424 and 465

we get,

$\tt→ 403= 1×13×<strong>31</strong>×403\\\tt→ 424= 1×2×7×14×<strong>31</strong>×62×217\\×424\\\tt→ 465= 1×3×5×<strong>3</strong><strong>1</strong>×93×155×465$

Hence,

the highest common factor is = 31

Therefore,

the capacity of a container 31 litre can measure the milk of all the container in an exact number of times.