Math, asked by sasi62, 3 months ago

Three different types of balls priced at 5, 8 and
13 per piece are displayed in three different boxes
by a trader. Mr. Paul bought from this shop all three
types of balls spending a total sum of 768. The
numbers of the balls he bought, taken in the order in
which the prices are mentioned above, are in the ratio
5:4:3. How many balls of the costliest variety did
he buy?​

Answers

Answered by piperrockellepragya
3

Answer:

Let the no of balls he bought is X

now putting in ratio = 5x+4x+3x

he paid for all balls is =768 so

for 5x+4x+3x=768

12x=768

x=768/12=64

so option B is your answer

Step-by-step explanation:

HOPE THIS HELPS PLEASE MARK AS BRAINLIEST.

Similar questions