Question

three digit natural number divisible by 6 find number of terms​

Answer 1

Answer:

102,108,114........996 are the three digits number divisible by 6

since 102, 108,.....996 are in AP

First term (a) = 102

common difference (d) = 108-102 = 6

last term or nth term (tn) = 996

let number of terms be n

tn = a+(n-1)d

996 = 102+(n-1)6

996-102 = 6n-6

894+6 = 6n

900 = 6n

6n = 900

n = 900/6 = 150

Therefore total number of terms = 150

There are 150 terms of 3 digit numbers which are divisible by 6.

I have applied this method you can solve it with any other method also but this is an easy one.

Answer 2

Answer:

Didi aap ka mai bhai hunga

mai 7 class mein parta huu..

Please don't say like that...