three digit number are made using three digit 4 5 9 without repeating the numbers among is selected at random what is the probability that the number Will
be multiple of 5
be multiple of 9
end with 9
Answers
Answer:
Answer: There can be three combination of the numbers 4,5,9
459,495,594,549,945,954
Therefore total number of possible outcomes=6
I)multiple of 5-495,945
No. Of favourable outcomes=2
P(getting multiple of 5)=2/6=1/3
II)multiple of 9
All the numbers are multiple of 9
No. Of favourable outcomes=6
P(getting a multiple of 9)=6/6=1
III)will end with zero
Nos. Ending with 9=549,459
No. Of favourable outcomes=2
P(getting a no. Which ends with zero)=2/6=1/3
I hope it helps
I think the other answer given by someone else given is wrong because all the nos. Are divisible by 9
Answer:
without repeating numbers,
possible 3 digit numbers are,
459
945
495
954
549
594
1)multiple of 5=945,495
p(E)=2/6 = 1/3
2)multiple of 9 = all numbers
p(E)=6/6 =1
3)end with 9=459.549
p(E)=2/6 = 1/3