Question

Three digit numbers are made using the digits 4, 5, 9 (without repetition). If a number among them is
selected at random, what is the probability that the number will:
4
(i) be a multiple of 5? (ii) be a multiple of 9 ? (iii) will end with 9 ?​

Answer 1

Step-by-step explanation:

total outcomes= 6

i) no. 945,495

probability =2/6

=1/3

ii) digits are 4,5,9 and their sum is divisible by nine

so probability =6/6

=1

iii) there will be 2 no. ending with 9= 549,459

probability = 2/6

=1/3