Three digit numbers formed by using digits 0, 1, 2 and 5 (without repetition) are written on different slips with distinct
numbers on each slip, and put in a bowl. One slip is drawn at random from the bowl, the probability that slip bears a
number divisible by '5'is
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Answer:
5/9 = 0.5556
Step-by-step explanation:
Total no. of outcome ( 3 digits no. )
As we have 4 digits number of 3 digit number can be formed are as follows
=> 3 × 3 ×2
=> 18 numbers
Note
- In 1st place we cannot consider 0 hence other three can be placed.
- In 1st place we cannot consider 0 hence other three can be placed.in 2nd place except the one placed in the 1st place any other three can be placed
- In 1st place we cannot consider 0 hence other three can be placed.in 2nd place except the one placed in the 1st place any other three can be placed in the 3rd place except the two which are placed in 1st and 2nd other 2 can be placed.
No. of favourable outcome ( divisible by 5 )
1st case 0 is placed in the end
=> 3 × 2 × 1
=> 6 numbers
2nd case 5 is placed in the last
=> 2 × 2 × 1
=> 4 numbers
Total = 6 + 4 = 10
Probability = favourable outcome / Total outcome
Probability = 10 / 18
Probability = 5/9 = 0.5556
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