Math, asked by vuggiralalasyasri, 9 months ago

Three distances are 8m, 9m 20cm and 10m 80cm long. What is the greatest possible length which can be used to measure these ropes?

Answers

Answered by angela89
1

Answer:

The given three ropes are 8m,9m,20cm and 10m,80cm long.We know that 1m=100cm , therefore,

Step-by-step explanation:

1st rope =8×100= 800cm

2nd rope =(9×100)+20=920

3rd rope = (10×100)+80=1080

Now , Let us factorize the length of the ropes as follows:

700=7×5×2×5×2

920=4×23×5×2

1080=2×2×3×3×3×2×5

The highest common factor (HCF)=5×2 =10

Hence , the greatest possible length that can be used to measure these ropes is 10cm.

Answered by rahulkumarbossomg2
0

Answer:

Three distances are 8 m, 9 m 20 cm and 10 m 80 cm long .what is the greatest possible length which can be used to measure these ropes?

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