Three distances are 8m, 9m 20cm and 10m 80cm long. What is the greatest possible length which can be used to measure these ropes?
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Answer:
The given three ropes are 8m,9m,20cm and 10m,80cm long.We know that 1m=100cm , therefore,
Step-by-step explanation:
1st rope =8×100= 800cm
2nd rope =(9×100)+20=920
3rd rope = (10×100)+80=1080
Now , Let us factorize the length of the ropes as follows:
700=7×5×2×5×2
920=4×23×5×2
1080=2×2×3×3×3×2×5
The highest common factor (HCF)=5×2 =10
Hence , the greatest possible length that can be used to measure these ropes is 10cm.
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Three distances are 8 m, 9 m 20 cm and 10 m 80 cm long .what is the greatest possible length which can be used to measure these ropes?
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