Three distinct prime numbers add up to 392. What is the minimum difference between the larger two of the given three prime numbers?
4
6
8
10
Answers
Answer:
6
Step-by-step explanation:
392 = 2 + 5 + 383
392 = 2 + 11 + 377
Difference between 383 - 377 = 6
Given: Three distinct prime numbers add up to 392.
To find The minimum difference between the larger two of the given three prime numbers.
Solution: Prime numbers are the numbers that can be divided by the number itself and the number one.
Distinct Prime numbers or a pair of distinct prime numbers are prime numbers say a,b, and a≠b. If we multiply a pair of distinct prime numbers, we get a number that is composite.
Now from above, three distinct prime numbers add up to 392.
So, 392 can be written as:
392=2+7+383 [∵ from 2 to 7, 3 and 5 are also prime numbers but if we add them with 2 and subtract it from 392, then we do not get a larger prime number.]
392=2+11+379
Now if we add 2+13+377=392 which is also a possible case, but it is written in the question the minimum difference. So, we subtract [383-377=6], which is not minimum according to option, and if we subtract [379-377=2], which is not given in option.
∴ The minimum difference = 383-379
= 4
Hence, the minimum difference between the larger two of the given three prime numbers is 4.