Three electric bulbs of rating 60 W each are joined in series and then connected to electric
mains. The power consumed by these three
bulbs will be
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Let resistance of each bulb is R
then total resistance of 3 bulbs=3R
power=V2/R =60W for each bulb
when three bulbs connected in series then power=
V2/(3R)
=(1/3)(V2/R)
=(1/3)(60)
=60/3 =20 W
(voltage is same when one bulb is used or three used.
hope it helps you!!!!!!!
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