Question

Three energy levels l1 , l2 and l3 of a hydrogen atom correspond to increasing values of energy i.e., 1 2 3 < < . e e e l l l if the wavelength corresponding to the transitions l3 to l2 , l2 to l1 and l3 to l1 and λ3 , λ2 and λ1 respectively then

Answer 1

As in Bohr's frequency,

λ = E2 - E1

λ = Eo - Eo / 4 = 3 Eo / 4

Eo = 4λ /3 ......(1)

It is for from L3 to L1  

Change in energy = E - 4 E/ 9 = 5E/9

λ =4Eo/9 - Eo4 = 7Eo/36....(2)  

Then sub (1) in (2)

5E/9  /  7E/36  = hc/ lambda  / hc/lambda prime

 

20/7   = lambda prime / lambda

lambda prime = 20 / 7 lambda

Answer 2

Answer:

Lambda' =27 lambda /7

Explanation:

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