Question

Three equal capacitances of 90 mF are connected in series, what is its equivalent capacitance?

Answer 1

Answer:

option a

Explanation:

hope this will help you!!

Answer 2

GiveN :-

• Three equal capacitances of 90 mF are connected in series.

To FinD :-

• The equivalent capacitance .

SolutioN :-

The value of each capacitors is 90 mF .

Say three capictors , C1 , C2 and C3 are connected in series , then the equivalent capacitance is given by ,

$\sf:\implies\pink{\dfrac{1}{C_{(net)}}= \dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3} }.\\\\\sf:\implies \dfrac{1}{C_{(net)}} = \dfrac{1}{90 \ mF } + \dfrac{1}{90 \ mF } + \dfrac{1}{90 \ mF } \\\\\sf:\implies \dfrac{1}{C_{(net)}}= 3\times \dfrac{1}{90\ mF} \\\\\sf:\implies \dfrac{1}{C_{(net)}}= \dfrac{1}{30 mF}\\\\\sf:\implies\underset{\blue{\sf Option \ a }}{\underbrace{\boxed{\pink{\frak{ C_{(net)}= 30 \ mF }}}}}$