Three equal capacitors joined in parallel take a total
charge of 1.8 uC from a 2 V cell. How much charge
will they take from the same cell, if joined in series?
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Explanation:
0.2μC
Let capacitance of each capacitor be C
Equivalent capacitance of three capacitor connect in parallel
C1=C+C+C
C1=3C
They are connected to a 2V battery
So charge stored
q=3CV
1.8μC=3CV
CV=0.6μC
After discharging the capacitor are connected in series
Now equivalent capacitance
Ceq1=C1+C1+C1
Ceq=3C
Now charge stored
q=3CV
q=0.2μC
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