Three equal charges each of 2.0X10^-6 are fixed at
those corners of an equilateral trangle of side 5 cm.
Find the coulomb force experienced by one of the
changes due to other two
please answer guys
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Answer:
F=q1×q2/4pi epsilon not ×r^2
=9×10^9×2×10^-6×2×10^-6/(5×10^-2)^2
=9×10^9×4/25×10^-4
=36×10^13/25
F =1.44×10^13
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