Question

three equal charges of 5 microcoulomb each are placed at the three vertices of an equilateral triangle of each side 5 cm each calculate the potential energy of the system of charge​

Answer 1

three equal charges of 5 microcoulomb each are placed at the three vertices of an equilateral triangle of each side 5 cm.

Let ABC is an equilateral triangle. potential energy of the configuration = potential energy of system A and B + potential energy of system B and C + potential energy of system C and A.

= kq²/l + kq²/l + kq²/l = 3kq²/l

where q = 5 microcoulomb and l = 5cm = 0.05m

so, potential energy of the configuration = 3 × 9 × 10^9 × (5 × 10^-6)²/(0.05)

= 27 × 10^9 × 25 × 10^-10/5

= 27 × 5 × 10^-1

= 13.5 J

Answer 2

Answer:

Explanation:

answer