three equal circle of unit radius touch each other. then the area of circle circumscribing these three circles is:
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Step-by-step explanation:
Let the O,A,B,C be the center of the circumscribing circle, and three touching circles respectively.
Area of ΔABC=43×a2
21×2×BD=3
BD=3
BO=32×BD
BO=32×3
BO=323
So, radius of circumscribing circle is =1+OB
=1+323
=33+23
Therefore, Area of circumscribing circle =πr2
=π(33+23)2
=3π(2+3)
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