Question

three equal cube are placed adjacently in row find the ratio of total surface area of the new cuboid to that of the surface area of the three cubes​

Answer 1

Answer:

Step-by-step explanation:

Let us assume the side to be 'a cm'

Then the Total surface area of the three cubes = 3×6×a^2

Now the new cuboid formed by placing the three cubes adjacent

the length formed is 3a cm while the height and the breadth remain the same as the sides of the cube that is a cm

Total surface area of the new cuboid = 2( lb + bh + lh )

= 2( 3a × a + a × a + 3a × a )

= 2( 7a^2)

Now TSA of cuboid / cube =

2 × 7 a^2 / 3 × 6 a^2

7/9

= 7:9

Answer 2

Answer:

Total surface area of the new cuboid = 2( lb + bh + lh )

= 2( 3a × a + a × a + 3a × a )

= 2( 7a^2)

Now TSA of cuboid / cube =

2 × 7 a^2 / 3 × 6 a^2

7/9

= 7:9

Step-by-step explanation: