Question

three equal cubes are placed adjacently in a row find the ratio of total surface area of the new cuboid to that the sum of the surface area of the three cubes

Answer 1

Length of resulting cuboid=3a
Breadth=a
Height=a
TSA=2(3a×a +a×a + a×3a)
=14a sq.
Sum of surface area of 3 cubes=
3× 6a sq.=18a sq.

Required ratio=14a sq./18a sq.
=7:9

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